4[5y-4(y-1)]=3[4(y+1)]

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Solution for 4[5y-4(y-1)]=3[4(y+1)] equation:


Simplifying
4[5y + -4(y + -1)] = 3[4(y + 1)]

Reorder the terms:
4[5y + -4(-1 + y)] = 3[4(y + 1)]
4[5y + (-1 * -4 + y * -4)] = 3[4(y + 1)]
4[5y + (4 + -4y)] = 3[4(y + 1)]

Reorder the terms:
4[4 + 5y + -4y] = 3[4(y + 1)]

Combine like terms: 5y + -4y = 1y
4[4 + 1y] = 3[4(y + 1)]
[4 * 4 + 1y * 4] = 3[4(y + 1)]
[16 + 4y] = 3[4(y + 1)]

Reorder the terms:
16 + 4y = 3[4(1 + y)]
16 + 4y = 3[(1 * 4 + y * 4)]
16 + 4y = 3[(4 + 4y)]
16 + 4y = [4 * 3 + 4y * 3]
16 + 4y = [12 + 12y]

Solving
16 + 4y = 12 + 12y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-12y' to each side of the equation.
16 + 4y + -12y = 12 + 12y + -12y

Combine like terms: 4y + -12y = -8y
16 + -8y = 12 + 12y + -12y

Combine like terms: 12y + -12y = 0
16 + -8y = 12 + 0
16 + -8y = 12

Add '-16' to each side of the equation.
16 + -16 + -8y = 12 + -16

Combine like terms: 16 + -16 = 0
0 + -8y = 12 + -16
-8y = 12 + -16

Combine like terms: 12 + -16 = -4
-8y = -4

Divide each side by '-8'.
y = 0.5

Simplifying
y = 0.5

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